Odpowiedź:
12.83
f(x) = ax + b
a = tgα , gdzie α jest katem nachylenia wykresu do osi OX
a)
f(x )= x + 1
a = 1
tgα = 1
α = 45°
b)
f(x) = - √3x + 1
a = - √3
tgα = - √3
α = 120°
c)
f(x)= (x - 1)/√3 = x/√3 - 1/√3 = (√3/3)x + √3/3
a = √3/3
tgα = √3/3
α = 30°
d)
f(x) = (-√3x+1)/√3= (- √3/√3)x + 1/√3 = (- 1)x + √3/3
a = - 1
tgα = - 1
α = 135°
