Odpowiedź:
a)
[tex]\frac{2x+3}{5} =\frac{2-x}{3} -x|*15\\3(2x+3)=5(2-x)-15x\\6x+9=10-5x-15x\\26x=1\\x=\frac{1}{26}[/tex]
b)
[tex]\frac{x+1}{2} -\frac{x-1}{3} =\frac{1}{4} |*12\\6(x+1)-4(x-1)=3\\6x+6-4x+4=3\\2x=-7\\x=-3,5[/tex]
c)
[tex]\frac{4x+7}{2} -\frac{5x-1}{6} =x+5|*6\\3(4x+7)-(5x-1)=6x+30\\12x+21-5x+1=6x+30\\x=8[/tex]
d)
[tex]\frac{x+5}{4} -\frac{2x+1}{8} =\frac{1}{2} (2-x)|*8\\2(x+5)-(2x+1)=4(2-x)\\2x+10-2x-1=8-4x\\4x=-1\\x=-\frac{1}{4}[/tex]
