a)
Pole podstawy
[tex] \frac{ {16}^{2} \sqrt{3} }{4} = \frac{256 \sqrt{3} }{4} = 64 \sqrt{3} {cm}^{2} [/tex]
Objętość
[tex] \frac{64 \sqrt{3} \times 12}{3} = 64 \sqrt{3} \times 4 = \boxed{256 \sqrt{3} {cm}^{3} }[/tex]
b)
Pole podstawy
[tex] {16}^{2} = 256 {cm}^{2} [/tex]
Objętość
[tex] \frac{256 \times 12}{3} = 256 \times 4 = \boxed{1024 {cm}^{3} }[/tex]
