f(-3) = 2 ⇒ A(-3,2)
f(6) = -1 ⇒ B(6,-1)
a)
[tex]\left \{ {{2 = -3a + b} \atop {-1 = 6a + b}} \right. \\\left \{ {{b = 2+3a} \atop {-1 = 6a + 2 + 3a}} \right. \\\left \{ {{b = 2+3a} \atop {-3 = 9a}} \right. \\\left \{ {{b = 2+3a} \atop {-\frac{3}{9} = a}} \right. \\\left \{ {{b = 2+3a} \atop {-\frac{1}{3} = a}} \right. \\\left \{ {{b = 2+3*(-\frac{1}{3}) } \atop {-\frac{1}{3} = a}} \right. \\\left \{ {{b = 2-1 } \atop {-\frac{1}{3} = a}} \right. \\\left \{ {{b = 1 } \atop {-\frac{1}{3} = a}} \right.\\\\y = -\frac{1}{3}x + 1[/tex]
b)
[tex]-\frac{1}{3}x + 1 = 0\\-\frac{1}{3}x = -1\\x = 3[/tex]
c) Załącznik
d)
[tex]5-9f(x)\leq x-1\\\\5 - 9(-\frac{1}{3}x + 1)\leq x-1\\5 + 3x - 9 \leq x - 1\\2x \leq 3\\x\leq \frac{3}{2}[/tex]
