Korzystam z twierdzenia Pitagorasa
[tex]a) \\ \\ {4}^{2} + {6}^{2} = {x}^{2} \\ 16 + 36 = {x}^{2} \\ {x}^{2} = 52 \\ x = \sqrt{52} \\ x = \sqrt{4 \times 13} \\ x = 2 \sqrt{13} [/tex]
[tex]b) \\ \\ {1}^{2} + {6}^{2} = {x}^{2} \\ {x}^{2} = 1 + 36 \\ x = \sqrt{37} [/tex]
[tex]c) \\ \\ {6}^{2} + {6}^{2} = {x}^{2} \\ 36 + 36 = {x}^{2} \\ x = \sqrt{72} \\ x = \sqrt{36 \times 2} \\ x = 6 \sqrt{2} [/tex]
