Odpowiedź:
[tex]\begin{cases}2x-3y-2=0\\\frac{x+y}{5}-\frac{x-y}{10}=1\ \ /\cdot10\end{cases}\\\\\\\begin{cases}2x-3y=2\\2(x+y)-(x-y)=10\end{cases}\\\\\\\begin{cases}2x-3y=2\\2x+2y-x+y=10\end{cases}\\\\\\\begin{cases}2x-3y=2\\x+3y=10\end{cases}\\\\\\\begin{cases}2x-3y=2\\x=10-3y\end{cases}\\\\\\2(10-3y)-3y=2\\\\20-6y-3y=2\\\\-9y=2-20\\\\-9y=-18\ \ /:(-9)\\\\y=2[/tex]
[tex]x=10-3\cdot2=10-6=4\\\\\begin{cases}x=4\\y=2\end{cases}[/tex]
