Odpowiedź :
[tex]zad.1\\\\\mid 2-\sqrt{5} -\sqrt{3} \mid -\mid 3-\sqrt{5} \mid +2\mid \sqrt{3} -1 \mid= -( 2-\sqrt{5} -\sqrt{3})-(3-\sqrt{5})+2(\sqrt{3} -1)=-2+\sqrt{5} +\sqrt{3}-3+\sqrt{5}+2\sqrt{3} -2=2\sqrt{5} +3\sqrt{3} -7\\\\\\zad.2\\\\\mid 1-\sqrt{13} +\sqrt{2} \mid -\mid \sqrt{13}-4 \mid +3\mid \sqrt{2} -1 \mid=-( 1-\sqrt{13} +\sqrt{2})-[-(\sqrt{13}-4)] +3(\sqrt{2} -1)=- 1+\sqrt{13} -\sqrt{2}-(-\sqrt{13}+4)+3\sqrt{2} -3=- 1+\sqrt{13} -\sqrt{2}+\sqrt{13}-4+3\sqrt{2} -3=2\sqrt{13} +2\sqrt{2} -8[/tex]