2.
[tex] \boxed{Odp.C}[/tex]
Ponieważ
[tex]98 + 27 = 125 \\ \\ {a}^{3} = 125 \\ a = \sqrt[3]{125} = 5[/tex]
3.
[tex]V = \frac{Pp \times H}{3}[/tex]
Pole podstawy
[tex] \frac{a \times h}{2} = \frac{10 \times 20}{2} = 10 \times 10 = 100 {cm}^{2} [/tex]
Zatem objętość
[tex] \frac{100 \times 20}{3} = \frac{2000}{3} = 666 \frac{2}{3} {cm}^{3} [/tex]
4.
a)
[tex] \frac{3}{4} + \frac{1}{4} \times \frac{2}{3} = \frac{3}{4} + \frac{2}{12} = \frac{9}{12} + \frac{2}{12} = \boxed{\frac{11}{12} }[/tex]
b)
[tex]24 \times 2 \div 8 \times 3 = 48 \div 8 \times 3 = 6 \times 3 = \boxed{18}[/tex]
c)
[tex] - 3^{2} + \frac{ {2}^{2} }{3} = - 9 + \frac{4}{3} = - \frac{9}{1} + \frac{4}{3} = - \frac{27}{3} + \frac{4}{3} = - \frac{23}{3} = \boxed{- 7 \frac{2}{3} }[/tex]
