Dane:
[tex]h_{1}[/tex] = 1m
[tex]V_{1}[/tex] = 10 [tex]\frac{m}{s}[/tex]
[tex]h_{2}[/tex] = 2m
[tex]V_{2}[/tex] = ?
Odpowiedź:
[tex]E_{p1}[/tex] + [tex]E_{k1}[/tex] = [tex]E_{p2}[/tex] + [tex]E_{k2}[/tex]
mg[tex]h_{1}[/tex] + [tex]\frac{mV_{1}^{2} }{2}[/tex] = mg[tex]h_{2}[/tex] + [tex]\frac{mV_{2}^{2} }{2}[/tex]
g[tex]h_{1}[/tex] + [tex]\frac{V_{1}^{2} }{2}[/tex] = g[tex]h_{2}[/tex] + [tex]\frac{V_{2}^{2} }{2}[/tex] /*2
2(g[tex]h_{1}[/tex])+[tex]V_{1} ^{2}[/tex] = 2(g[tex]h_{2}[/tex]) + [tex]V_{2}[/tex]
[tex]V_{2}[/tex] = [tex]\sqrt{2(gh_{1})+V_{1} ^{2}-2(gh_{2})}[/tex] = [tex]\sqrt{20 +100-40}[/tex] = [tex]\sqrt{80}[/tex] ≈ 9 [[tex]\frac{m}{s}[/tex]]
