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Rozwiązane

1.Oblicz.
a)2222 11/117:4444 22/117
b)133 5/222:399 15/222
c)222 4/17:333 6/17
d)4 231/1000:12 693)1000​

1Oblicz A2222 111174444 22117 B133 5222399 15222c222 417333 617 D4 231100012 6931000 class=

Odpowiedź :

Ryszardczernyhowskigo

Odpowiedź:

1.

a)  2222 11/117  :  4444 22/117 =

= 259985/519970 = 1/2

b)   133 5/222:399 15/222 =

= 29531/222 • 222/88593 = 1/3

c)  ( 222•17/17 + 4/17) : ( 333•17/17 + 6/17) =

= 5778/5667 = 1,019587083112

d)  4 231/1000:12 693/1000 =

(4231/1000)(1000/12693) = 1/3

Szczegółowe wyjaśnienie:

1.

a)  2222 11/117  :  4444 22/117 =

= (259974/117 + 11/117) : (519948/117 + 22/117) =

= (259985/117) : (519970/117) = (259985/117) • (117/519970) =

= 259985/519970 = 1/2

b)   133 5/222:399 15/222 =

= (29526/222 + 5/222) : (88578/222 + 15/222)=

= (29531/222) : (88593/222) =

= 29531/222 • 222/88593 = 1/3

c)  ( 222•17/17 + 4/17) : ( 333•17/17 + 6/17) =

= 3774/17 + 4/17) : (5661/17 + 6/17) =

= (5778/17) : (5667/17) = (5778/17)•17/5667 =

= 5778/5667 = 1,019587083112

d)  4 231/1000:12 693/1000 =

(4000/1000 + 231/1000):(12000/1000 + 693/1000) =

= (4231/1000) : (12693/1000) =

(4231/1000)(1000/12693) = 1/3

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