[tex]stary\ trapez:\\\\podstawa:\ a\\podstawa:\ \ b\\wysokosc\ trapezu :\ \ h\\\\P=\frac{a+b}{2}*h\\\\nowy\ trapez:\\\\podstawa:\ a+2\\podstawa:\ \ b+2\\wysokosc\ trapezu :\ \ 3h\\\\P_{1}=\frac{a+2+b+2}{2} =\frac{a +b+4}{2}*3h\\\\P_{1}-P=\frac{a +b+4}{2}*3h -\frac{a+b}{2}*h=\frac{(a +b+4)*3h}{2} -\frac{(a+b)*h}{2}=\\\\=\frac{3ah +3bh+12h-ah-bh}{2} =\frac{3ah +3bh+12h-ah-bh}{2} = \frac{2ah+2bh+12h}{2}\\\\= \frac{2h(a+b+6)}{2}=(a+b+6)h[/tex]
[tex]odp.\ Pole\ nowego\ trapezu\ bedzie\ wieksze\ o\ (a+b+6)h.[/tex]
