Odpowiedź:
[tex]a)\\\\2(5x-4)-5(x-3)=x-2(3x-0,5)\\\\10x-8-5x+15=x-6x+1\\\\5x+7=-5x+1\\\\5x+5x=1-7\\\\10x=-6\ \ /:10\\\\x=-\frac{6}{10}\\\\x=-\frac{3}{5}\\\\\\b)\\\\x-2(x-1)=0,2(1-2x)\\\\x-2x+2=0,2-0,4x\\\\-x+0,4x=0,2-2\\\\-0,6x=-1,8\ \ /:(-0,6)\\\\x=3[/tex]
[tex]c)\\\\\frac{4x+7}{2}-\frac{5x-1}{6}=x+5\ \ /\cdot6\\\\3(4x+7)-(5x-1)=6x+30\\\\12x+21-5x+1=6x+30\\\\7x+22=6x+30\\\\7x-6x=30-22\\\\x=8\\\\\\d)\\\\\frac{x+5}{4}-\frac{2x+1}{8}=\frac{1}{2}(2-x)\\\\\frac{x+5}{4}-\frac{2x+1}{8}=1-\frac{1}{2}x\ \ /\cdot8\\\\2(x+5)-(2x+1)=8-4x\\\\2x+10-2x-1=8-4x\\\\9=8-4x\\\\4x=8-9\\\\4x=-1\ \ /:4\\\\x=-\frac{1}{4}[/tex]
