Odpowiedź :
1.
[tex]3\sqrt{12}-\sqrt{27} = 3\sqrt{4\cdot3}-\sqrt{9\cdot3} = 3\cdot\sqrt{4}\cdot\sqrt{3}-\sqrt{9}\cdot\sqrt{3}=3\cdot2\sqrt{3}-3\sqrt{3} =\\\\=6\sqrt{3}-3\sqrt{3} = 3\sqrt{3}=3\cdot3^{\frac{1}{2}} = 3^{\frac{3}{2}} = 3^{1,5}[/tex]
2.
[tex]sin135^{o}-cos45^{o} = sin(90^{o}+45^{o})-cos45^{o} = cos45^{o}-cos45^{o} = 0[/tex]