[tex]c)\\\\\frac{4,25-4\frac{1}{3} }{3\frac{1}{3}-3,5} =\frac{4 \frac{25}{100}-4\frac{1}{3} }{3\frac{1}{3}-3 \frac{5}{10}} =\frac{4 \frac{1}{4}-4\frac{1}{3} }{3\frac{1}{3}-3 \frac{1}{2}} =\frac{4 \frac{3}{12}-4\frac{4}{12} }{3\frac{2}{6}-3 \frac{3}{6}} =\frac{-\frac{1}{12}}{-\frac{1}{6}} =(-\frac{1}{12}):(-\frac{1}{6})=\\\\= (-\frac{1}{\not{12}^2})*(-\frac{\not{6}^1}{1})= \frac{1}{2}[/tex]
