Odpowiedź :
a) mSO3=32u+3*16u=80 u
32u---x%
80u---100%
x=40%S
100%-40%=60%O
b) mAl2S3=2*27u+3*32u=150 u
54u---x%
150u---100%
x=36%Al
100%-36%=64%S
a) mSO3=32u+3*16u=80 u
32u---x%
80u---100%
x=40%S
100%-40%=60%O
b) mAl2S3=2*27u+3*32u=150 u
54u---x%
150u---100%
x=36%Al
100%-36%=64%S