pls na szybko daje naj

[tex]a)\\\\\frac{\not{10}^5\not{\sqrt{2}}}{\not{2} \not{\sqrt{2}}} =5\\\\\\b)\\\\3\sqrt{11}+5\sqrt{11}=8\sqrt{11}\\\\\\c)\\\\\frac{6+2\sqrt[3]{9}}{2}=\frac{\not{6}^3 }{\not{2}^1}+\frac{\not{2}^1\sqrt[3]{9}}{\not{2}^1}=3\sqrt[3]{9}\\\\\\d)\\\\4\sqrt[3]{10}+2\sqrt[3]{10}+3\sqrt[3]{-10}=4\sqrt[3]{10}+2\sqrt[3]{10}-3\sqrt[3]{ 10}=3\sqrt[3]{10}[/tex]