Odpowiedź :
[tex]dla \space x = - 3 \\ \\ (x - 5)(2x + 1) = 2 {x}^{2} + x - 10x - 5 = \\ = 2 \times {( - 3)}^{2} + ( - 3) - 10 \times ( - 3) - 5 = \\ = 2 \times 9 - 3 + 30 - 5 = \\ = 18 + 22 = 40[/tex]
[tex]dla \space x = - 3 \\ \\ (x - 5)(2x + 1) = 2 {x}^{2} + x - 10x - 5 = \\ = 2 \times {( - 3)}^{2} + ( - 3) - 10 \times ( - 3) - 5 = \\ = 2 \times 9 - 3 + 30 - 5 = \\ = 18 + 22 = 40[/tex]