Zad 9 str 168matematyka klasa 6 pomóżcie pllis

Odpowiedź:
a)
[tex] \frac{0.2 + 2 \times 1\frac{3}{4} }{0.37} = \frac{0.2 + 2 \times \frac{7}{4} }{0.37} = \frac{0.2 + \frac{14}{4} }{0. 37} = \frac{0.2 + 3.5}{0.37} = \frac{3.7}{0.37} = 10[/tex]
b)
[tex] \frac{ \frac{1}{3} \times {3}^{2} \times ( - \frac{1}{3})^{2} }{ (- \frac{1}{3} )} = \frac{ \frac{1}{3} \times 9 \times ( - \frac{1}{3}) }{ ( - \frac{1}{3}) } = 3[/tex]
c)
[tex] \frac{0.32 \times ( - 0.6 - 0.3)}{3.6} = \frac{0.32 \times ( - 0.9)}{3.6} = \frac{0.32}{ - 4} = - 0.08[/tex]
d)
[tex] \frac{(5 \times \frac{1}{3}) \times ( \frac{1}{10} - 1) }{1\frac{1}{8} } = \frac{ \frac{5}{3} \times (- \frac{9}{10} )}{ \frac{9}{8} } = - \frac{3}{2} \times \frac{8}{9} = - \frac{4}{3} = - 1 \frac{1}{3} [/tex]