Dane:
F₁ = 1 kN = 1000 N (→)
F₂ = 5 hN = 500 N (←)
Fw = F₁ - F₂ = 1000 N - 500 N = 500 N
a = 20 m/s²
Szukane:
m = ?
Rozwiązanie
[tex]F_{w} = m\cdot a\ \ /:a\\\\m = \frac{F_{w}}{a}\\\\m = \frac{500 \ N}{2\frac{m}{s^{2}}} = \frac{500 \ kg\cdot\frac{m}{s^{2}}}{2\frac{m}{s^{2}}}}\\\\\boxed{m = 250 \ kg}[/tex]
