Dodawanie
[tex]2\dfrac{5}{6}+1\dfrac{1}{9}=2\dfrac{5\cdot3}{6\cdot3}+1\dfrac{1\cdot2}{9\cdot2}=2\dfrac{15}{18}+1\dfrac{2}{18}=\boxed{3\dfrac{17}{18}}\\[/tex]
Odejmowanie
[tex]2\dfrac{5}{6}-1\dfrac{1}{9}=2\dfrac{15}{18}-1\dfrac{2}{18}=\boxed{1\frac{13}{18}}\\[/tex]
Mnożenie
[tex]2\dfrac{5}{6}\cdot1\dfrac{1}{9}=\dfrac{2\cdot6+5}{6}\cdot\dfrac{1\cdot9+1}{9}=\dfrac{12+5}{6}\cdot\dfrac{9+1}{9}=\dfrac{17}{6}\cdot\dfrac{10}{9}=\\\\\\=\dfrac{17}{3}\cdot\dfrac{5}{9}=\dfrac{75}{27}=2\dfrac{21}{27}=2\dfrac{21:3}{27:3}=\boxed{2\dfrac{7}{9}}[/tex]
Dzielenie
[tex]2\dfrac{5}{6}:1\dfrac{1}{9}=\dfrac{17}{6}:\dfrac{10}{9}=\dfrac{17}{6}\cdot\dfrac{9}{10}=\dfrac{17}{2}\cdot\dfrac{3}{10}=\dfrac{51}{20}=\boxed{2\dfrac{11}{20}}\\[/tex]
