Odpowiedź :
Odpowiedź:
1.
[tex] {(2x + 3)}^{2} = {4x}^{2} + 12x + 9 [/tex]
2.
[tex](x - 6)(x + 6) + (x + 1)(x - 1) = \\ = {x}^{2} - 36 + {x}^{2} - 1 = \\ = 2 {x}^{2} - 37 [/tex]
3.
[tex] {(x - 1)}^{2} + {(x - 3)}^{2} = \\ = {x}^{2} - 2x + 1 + {x}^{2} - 6x + 9 = \\ = 2 {x}^{2} - 8x + 10[/tex]