Odpowiedź :
[tex]Dane:\\m = 0,5 \ kg\\S = 0,002 \ m^{2}\\g = 10\frac{N}{kg}\\Szukane:\\p = ?\\\\\\p = \frac{F}{S}\\\\ale \ \ F = m\cdot g = 0,5 \ kg\cdot10\frac{N}{kg} = 5 \ N\\\\p = \frac{5 \ N}{0,002 \ m^{2}}\\\\\boxed{p = 2 \ 500 \ Pa = 2,5 \ kPa}[/tex]