Odpowiedź :
[tex]Dane:\\F = 100 \ N\\S = 5 \ 000 \ cm^{2} = 0,5 \ m^{2}\\Szukane:\\p = ?\\\\\\p = \frac{F}{S}\\\\p = \frac{100 \ N}{0,5 \ m^{2}}\\\\\boxed{p = 200 \ Pa}[/tex]
Odp. Szukane ciśnienie p = 200 Pa.
[tex]Dane:\\F = 100 \ N\\S = 5 \ 000 \ cm^{2} = 0,5 \ m^{2}\\Szukane:\\p = ?\\\\\\p = \frac{F}{S}\\\\p = \frac{100 \ N}{0,5 \ m^{2}}\\\\\boxed{p = 200 \ Pa}[/tex]
Odp. Szukane ciśnienie p = 200 Pa.