Odpowiedź:
[tex]v = \frac{1}{2}a \frac{a \sqrt{3} }{2}h = \frac{ {a}^{2} \sqrt{3} }{4} h \\ \\ v = \frac{{(6cm)}^{2} \sqrt{3} }{4} 8cm = 36 {cm}^{2} \sqrt{3} \times 2cm = 72 \sqrt{3} {m}^{2} [/tex]
[tex]pc = 2 \times pp + 3 \times ppb = 2 \frac{ {a}^{2} \sqrt{3} }{4} + 3ah = \frac{ {a}^{2} \sqrt{3} }{2} + 3 \times 6cm \times 8cm = \frac{( {6cm)}^{2} \sqrt{3} }{2} + 144 {cm}^{2} = (18 \sqrt{3} + 144 ){cm}^{2} [/tex]
