Odpowiedź:
[tex]4(3x-5)+2(4-2x)=12x-20+8-4x=8x-12\\\\\\3(2k+1)+5(2+3k)=6k+3+10+15k=21k+13\\\\\\2(x+2y-3)+5(x-3y-4)=2x+4y-6+5x-15y-20=7x-11y-26\\\\\\5(2a+4)+4(0,5-2a)=10a+20+2-8a=2a+22\\\\\\2(6z+2y)-3(y-z)=12z+4y-3y+3z=15z+y\\\\\\a(3a+4b-c)-3(ab+a^2-4ac)=3a^2+4ab-ac-3ab-3a^2+12ac=\\\\=ab+11ac\\\\\\5x(2x+2y-3)-2(4xy-2+6x^2)=10x^2+10xy-15x-8xy+4-12x^2=\\\\=-2x^2+2xy-15x+4[/tex]
[tex]3ab(2a+3b-4)-2a(7ab-b+4b^2)=6a^2b+9ab^2-12ab-14a^2b+2ab-8ab^2=\\\\=-8a^2b+ab^2-10ab[/tex]
