[tex]Dane:\\m = 150 \ kg\\h_1 = 350 \ m\\h_2 = 500 \ m\\\Delta h = h_2-h_1 = (500-350)m = 150 \ m\\g = 10\frac{N}{kg}\\Szukane:\\\Delta E_{p} = ?\\\\Rozwiazanie\\\\\Delta E_{p} = m\cdot\Delta h \cdot g\\\\\Delta E_{p} = 150 \ kg \cdot150 \ m\cdot10\frac{N}{kg}\\\\\boxed{\Delta E_{p} = 225 \ 000 \ J = 225 \ kJ}\\\\(1 \ kJ = 1000 \ J)[/tex]
