Odpowiedź :
Dane:
a = 20cm = 0,20m
b = 21cm = 0,21m
Fn = 25N
szukane:
p = ?
p = [tex]\frac{Fn}{S}[/tex]
S = a*b
p = [tex]\frac{25}{0,20*0,21} = \frac{25N}{0,042}[/tex] ≈ 595Pa = 5,95hPa
Liczę na naj
Dane:
a = 20cm = 0,20m
b = 21cm = 0,21m
Fn = 25N
szukane:
p = ?
p = [tex]\frac{Fn}{S}[/tex]
S = a*b
p = [tex]\frac{25}{0,20*0,21} = \frac{25N}{0,042}[/tex] ≈ 595Pa = 5,95hPa
Liczę na naj