Odpowiedź :
1) mC8H14=8*12u+14*1u=110u
96u---x%
110u---100%
x=87,27%C
100%-87,27%=12,73%H
2) C10H18+2HI--->C10H20I2
C6H12+Br2--->C6H12Br2
C5H8+2Br2--->C5H8Br4
1) mC8H14=8*12u+14*1u=110u
96u---x%
110u---100%
x=87,27%C
100%-87,27%=12,73%H
2) C10H18+2HI--->C10H20I2
C6H12+Br2--->C6H12Br2
C5H8+2Br2--->C5H8Br4