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1 i 4/13 - 9/13 i 6 i 8/9 - 4 i 2/3 mam na teraz

Odpowiedź :

Odpowiedź:

[tex]1\dfrac{4}{13}-\dfrac{9}{13}=\dfrac{1\cdot13+4}{13}-\dfrac{9}{13}=\dfrac{13+4}{13}-\dfrac{9}{13}=\dfrac{17}{13}-\dfrac{9}{13}=\boxed{\frac{8}{13}}\\\\\\6\dfrac{8}{9}-4\dfrac{2}{3}=6\dfrac{8}{9}-4\dfrac{2\cdot3}{3\cdot3}=6\dfrac{8}{9}-4\dfrac{6}{9}=\boxed{2\frac{2}{9}}[/tex]