Odpowiedź:
[tex]a)\ \ 2x^2+5x-5\\\\a=2\ \ ,\ \ b=5\ \ ,\ \ c=-5\\\\\Delta=b^2-4ac\\\\\Delta=5^2-4\cdot2\cdot(-5)=25+40=65\\\\\\p=\frac{-b}{2a}=\frac{-5}{2\cdot2}=\frac{-5}{4}=-\frac{5}{4}\\\\q=\frac{-\Delta}{4a}=\frac{-65}{4\cdot2}=-\frac{65}{8}=-8\frac{1}{8} \\\\y=a(x-p)^2+q\\\\y=2(x-(-\frac{5}{4}))^2+(-8\frac{1}{8})\\\\y=2(x+\frac{5}{4})^2-8\frac{1}{8}[/tex]
