Odpowiedź:
1.
a) 5³ = 5∙5∙5 = 125; 2⁵ = 2∙2∙2∙2∙2 = 32, (-3)⁴ = + 81, (-4)³ = -64
b) 0⁶ = 0 (1i3/7)¹ = 1i3/7, (-1)⁴ = +1, (-10)° = -1 2
c) (1/2)⁵ = 1/32, (-3/5)⁴ = 81/625; 0,2⁶ = 0,00064; (-0,03) = - 0,000027
d) (-1,1)² = + 1,21; (1i1/4)³ = (4/4 +1/4)³ = (5/4)³ = 25/16,
(-2i1/5)³ = (-10/5 - 1/5)³ = (-11/5)³ = - 1331/125; 1,3² = 1,69
e) -3⁴ = - 81, -(-1,5)³ = + 3,375; -1,1² = -1,21; -(-2/3)⁴ = - 16/81
f) 2³/3 = 8/3, (-3)²/2 = 9/2, 2/3² = 2/9, -5/(-3)² = -5/9
Szczegółowe wyjaśnienie:
1.
a) 5³ = 5∙5∙5 = 125; 2⁵ = 2∙2∙2∙2∙2 = 32, (-3)⁴ = + 81, (-4)³ = -64
b) 0⁶ = 0 (1i3/7)¹ = 1i3/7, (-1)⁴ = +1, (-10)° = -1 2
c) (1/2)⁵ = 1/32, (-3/5)⁴ = 81/625; 0,2⁶ = 0,00064; (-0,03) = - 0,000027
d) (-1,1)² = + 1,21; (1i1/4)³ = (4/4 +1/4)³ = (5/4)³ = 25/16,
(-2i1/5)³ = (-10/5 - 1/5)³ = (-11/5)³ = - 1331/125; 1,3² = 1,69
e) -3⁴ = - 81, -(-1,5)³ = + 3,375; -1,1² = -1,21; -(-2/3)⁴ = - 16/81
f) 2³/3 = 8/3, (-3)²/2 = 9/2, 2/3² = 2/9, -5/(-3)² = -5/9
