Odpowiedź:
[tex]\begin{cases}2x-3y=4-\frac{1}{3}y\ \ /\cdot3\\-x+5y=2x-2y+2\end{cases}\\\\\\\begin{cases}6x-9y=12-y\\-x+5y-2x+2y=2\end{cases}\\\\\\\begin{cases}6x-9y+y=12\\-3x+7y=2\end{cases}\\\\\\\begin{cases}6x-8y=12\ \ /:2\\-3x+7y=2\end{cases}\\\\\\+\begin{cases}3x-4y=6\\-3x+7y=2\end{cases}\\---------\\3y=8\ \ /:3\\\\y=\frac{8}{3}\\\\\\-3x+7\cdot\frac{8}{3}=2\\\\-3x+\frac{56}{3}=2\\\\-3x=2-\frac{56}{3}\\\\-3x=\frac{6}{3}-\frac{56}{3}\\\\-3x=-\frac{50}{3}\ \ /:(-3)\\\\x=\frac{50}{3}:3[/tex]
[tex]x=\frac{50}{3}\cdot\frac{1}{3}\\\\x=\frac{50}{9}\\\\\\\begin{cases}x=\frac{50}{9}\\y=\frac{8}{3}\end{cases}[/tex]
