Odpowiedź:
zad 3
a)
log₃2/9 + log₃1/6 = log₃(2/9 * 1/6) = log₃2/54 = log₃1/27 = - 3
b)
log₂10+ log₂1,6 = log₂(10 * 1,6) = log₂16 = 4
c)
log25 + log4 = log(25 * 4) = log100 = 2
d)
log₅√10 - log₅√2 = log₅(√(10/2)= log₅√5 = 1/2
e)
log9 - log0,9= log(9/0,9) = log10 = 1
f)
log₈7 - log₈14 = log₈7/14= log₈1/2 = - 1/3
