[tex](x+1)^3=0\\
x+1=0\\
x=-1\\\\
\displaystyle
V=\pi \int \limits_{-1}^0((x+1)^3)^2\, dx=\pi \int \limits_{-1}^0(x+1)^6\, dx=\\
V=\pi \left[\dfrac{(x+1)^7}{7}\right]_{-1}^0\\
V=\pi \left(\dfrac{(0+1)^7}{7}-\dfrac{(-1+1)^7}{7}\right)\\
V=\pi \left(\dfrac{1}{7}-0\right)\\
V=\dfrac{\pi}{7}[/tex]
