[tex]\frac{2(x+4)}{4} -\frac{x+8}{3} =y+\frac{x}{4} \\5x-2y=-9\\\\\frac{2x+8}{4} -\frac{x+8}{3} =y+\frac{x}{4}|\cdot12\\5x-2y=-9\\\\3(2x+8)-4(x+8)=12y+3x\\5x-2y=-9\\\\6x+24-4x-32=12y+3x\\5x-2y=-9\\\\2x-8=12y+3x\\5x-2y=-9\\\\2x-12y-3x=8\\5x-2y=-9\\\\-x-12y=8|\cdot5\\5x-2y=-9\\\\-5x-60y=40\\5x-2y=-9\\+------------\\-62y=31|:(-62)\\\boxed{y=-\frac{1}{2}} \\5x-2\cdot(-\frac{1}{2} )=-9\\5x-(-1)=-9\\5x+1=-9\\5x=-9-1\\5x=-10 |:5\\\boxed{x=-2}[/tex]
