Odpowiedź :
[tex](x-2)(x+2)\leq (x+3)^2\\ x^2-4\leq x^2+6x+9\\ -4-9\leq 6x\\ -13\leq 6x\\ -\frac{13}{6}\leq x\\ x\geq -\frac{13}{6}\\ x\geq -2\frac{1}{6}[/tex]
[tex](x-2)(x+2)\leq (x+3)^2\\ x^2-4\leq x^2+6x+9\\ -4-9\leq 6x\\ -13\leq 6x\\ -\frac{13}{6}\leq x\\ x\geq -\frac{13}{6}\\ x\geq -2\frac{1}{6}[/tex]