[tex]Dane:\\V = 0,005 \ m^{3}\\d = 1000\frac{kg}{m^{3}} \ - \ gestosc \ wody\\g = 10\frac{N}{kg}\\Szukane:\\F_{w} = ?\\\\Rozwiazanie\\\\F_{w} = d\cdot g\cdot V\\\\F_{w} = 1000\frac{kg}{m^{3}}\cdot10\frac{N}{kg}\cdot0,005 \ m^{3}\\\\\boxed{F_{w} = 50 \ N}[/tex]
