Odpowiedź :
Odpowiedź:
[tex]a)y=ax+b\\\left \{ {{3=-3a+b} \atop {3=6a+b}} \right. \\\left \{ {{b=3+3a} \atop {3=6a+3+3a}} \right. \\\left \{ {{b=3+3a} \atop {a=0}} \right. \\\left \{ {{a=0} \atop {b=3}} \right. \\\\y=3\\b)\left \{ {{-2=-4a+b} \atop {1=2a+b}} \right. <=>\left \{ {{b=4a-2} \atop {1=2a+4a-2}} \right.<=>\left \{ {{b=0} \atop {a=\frac{1}{2} }} \right. \\y=\frac{1}{2} x\\d)\left \{ {{b=4-3a} \atop {6=7a+4-3a}} \right. <=>\left \{ {{b=2\frac{1}{2} } \atop {a=\frac{1}{2} }} \right. \\y=\frac{1}{2} x+1\frac{1}{2}[/tex]
[tex]c)\left \{ {{b=3} \atop {6=7a+3}} \right. <=>\left \{ {{b=3} \atop {a=\frac{3}{7} }} \right.\\y= \frac{3}{7}x+3[/tex]