Proszę o zrobienie tego zadania z góry dziękuję

Odpowiedź:
motocykl:
v=100km/h=27,7m/s
a=Δv/t
a=27,7m/s /10s
a=2,7m/s²
v(5)=2,7m/s²*5s=13,5m/s=48,6km/h
v(15)=2,7m/s²*15s=40,5m/s=145,8km/h
v(20)=2,7m/s²*20s=54m/s=194,4km/h
v(25)=54m/s=194,4km/h
v(30)=54m/s=194,4km/h
samochód:
v=25km/h=6,94m/s
a=6,94m/s/5s
a=1,39m/s²
v(10)=1,39m/s²*10s=13,9m/s=50km/h
v(15)=1,39m/s²*15s=20,85m/s=75km/h
v(20)=1,39m/s²*20s=27,8m/s=100km/h
v(25)=1,39m/s²*25s=34,75m/s=125km/h
v(30)=1,39m/s²*30s=41,7m/s=150km/h
b)
v1=v2=54m/s=194,4km/h
t2=v2/a2
t2=54m/s / 1,39m/s²
t2=38,8s
s1=a1*t²/2 + v*(t2-20)
s1=2,7m/s²*(20s)²/2 + 54m/s*18,8s
s1=1555,2m
s2=a2t²/2
s2=1,39m/s²*(38,8s)²/2
s2=1046,3m
s1>s2
motor był dalej
Wyjaśnienie: