Odpowiedź :
Odpowiedź:
a. (x-3)(x²+2x-1)=x³+2x²-x-3x²-6x+3=
=x³-x²-7x+3
b. (x+2)(1-3x-x²)=x-3x²-x³+2-6x-2x²=
=-x³-5x²-5x+2
c. (x+4)(x²-3x-2)=x³-3x²-2x+4x²-12x-8=
=x³+x²-14x-8
d. (2x-1)(4x²-x+2)=8x³-2x²+4x-4x²+x-2=
=8x³-6x²+5x-2
Odpowiedź:
a. (x-3)(x²+2x-1)=x³+2x²-x-3x²-6x+3=
=x³-x²-7x+3
b. (x+2)(1-3x-x²)=x-3x²-x³+2-6x-2x²=
=-x³-5x²-5x+2
c. (x+4)(x²-3x-2)=x³-3x²-2x+4x²-12x-8=
=x³+x²-14x-8
d. (2x-1)(4x²-x+2)=8x³-2x²+4x-4x²+x-2=
=8x³-6x²+5x-2