Odpowiedź:
Liczby wymierne to takie,które można zapisać w postaci ułamka zwykłego
np. 5=5/1 , 1 7/8 = 15/8 , -3 = (-3)/1 , √4 = 2 = 2/1
[tex]A.\\\\\sqrt{25}=5\\\\\sqrt[3]{-8}=-2\\\\\sqrt{1\frac{1}{4}}=\sqrt{\frac{5}{4}}=\frac{\sqrt{5} }{2}\\\\\sqrt{0,064}=\sqrt{\frac{64}{100}}=\sqrt{\frac{16}{25}}=\frac{4}{5}\\\\\\B.\\\\\sqrt[3]{0,001}=\sqrt[3]{\frac{1}{1000}}=\frac{1}{10}\\\\\sqrt{1\frac{7}{9}}=\sqrt{\frac{16}{9}}=\frac{4}{3}\\\\\sqrt{16}=4\\\\\sqrt[3]{-64}=-4[/tex]
[tex]C.\\\\\sqrt{\frac{1}{4}}=\frac{1}{2}\\\\\sqrt[3]{-0,001}=-0,1=-\frac{1}{10}\\\\\sqrt[3]{27}=3\\\\\sqrt{4\frac{1}{16}}=\sqrt{\frac{65}{16}}=\frac{\sqrt{65}}{4}[/tex]
[tex]D.\\\\\sqrt[3]{-125}=-5\\\\\sqrt[3]{9}\approx2,08008\\\\\sqrt{0,004}=\sqrt{\frac{4}{1000}}=\sqrt{\frac{1}{250}}=\frac{1}{\sqrt{250}}=\frac{1}{\sqrt{25\cdot10}}=\frac{1}{5\sqrt{10}}\cdot\frac{\sqrt{10}}{\sqrt{10}}=\frac{\sqrt{10}}{50}\\\\\sqrt{\frac{9}{16}}=\frac{3}{4}[/tex]
Odp.B
