Odpowiedź :
Objętość walca liczymy ze wzoru:
[tex]V = P_{p}\cdot h = \pi r^{2}h\\\\1.\\h = 9 \ cm, \ \ r=4 \ cm\\\\V = \pi r^{2}h = \pi\cdot4^{2}\cdot9=16\cdot 9\pi\\\\\boxed{V = 144\pi \ cm^{3}}}\\\\2.\\h = 7 \ cm, \ r = 3 \ cm\\\\V = \pi r^{2}h = \pi\cdot3^{2}\cdot7 = 9\cdot7\pi\\\\\boxed{V = 63\pi \ cm^{3}}}[/tex]
[tex]3.\\h = 5 \ cm, \ \ r = 1 \ cm\\\\V = \pi r^{2}h = \pi\cdot1^{2}\cdot 5\\\\\boxed{V = 5\pi \ cm^{3}}[/tex]