Odpowiedź :
[tex]\frac{9w+12m-3}{-3} = \frac{9w}{-3}+\frac{12m}{-3}-\frac{3}{-3} = -3w-4m+1\\\\\frac{8a-4(b-2)}{2} = \frac{8a}{2}-\frac{4(b-2)}{2} = 4a-2(b-2)[/tex]
[tex]\frac{9w+12m-3}{-3} = \frac{9w}{-3}+\frac{12m}{-3}-\frac{3}{-3} = -3w-4m+1\\\\\frac{8a-4(b-2)}{2} = \frac{8a}{2}-\frac{4(b-2)}{2} = 4a-2(b-2)[/tex]