Bardzo proszę o pomoc z góry dziękuje zadanie w załączniku

[tex]f(x)=\dfrac{x-11}{2x} ~~zal.~~2x\neq 0~~\Rightarrow~~x\neq 0\\\\Df(x)=R- \{ 0 \}\\\\f(x)=\dfrac{x-11}{2x}~~\land ~~f(x)=-\sqrt{3} ~~\Rightarrow ~~\dfrac{x-11}{2x}=-\sqrt{3}\\\\\dfrac{x-11}{2x}=\dfrac{-\sqrt{3} }{1} \\\\x-11=-2\sqrt{3}\cdot x\\\\x+-2\sqrt{3}\cdot x=11\\x\cdot (1+2\sqrt{3})=11~~\mid \div (1+2\sqrt{3})\\\\x=\dfrac{11}{1+2\sqrt{3} } \\\\x=\dfrac{11}{1+2\sqrt{3} } \cdot \dfrac{1-2\sqrt{3} }{1-2\sqrt{3} } \\\\x=\dfrac{11\cdot (1-2\sqrt{3} ) }{1^{2} -(2\sqrt{3} )^{2} } \\\\[/tex]
[tex]x=\dfrac{11-22\sqrt{3} }{1-12} \\\\x=\dfrac{11-22\sqrt{3} }{-11} \\\\x=-1+2\sqrt{3} \\\\Od: ~~x=-1+2\sqrt{3}[/tex]