Odpowiedź :
a) pewnie chodzi o KCl - 39u + 35,5u = 74,5u
b) H2SO4 - 2 • 1u + 32u + 4 • 16u
= 2u + 32u + 64u=
= 98u
c) (NH4)2CO3 =
2(14u + 4•1u) + 12u + 48u=
2(18u) + 12u + 48u=
36u + 12u + 48u =
=96u
b) H2SO4 - 2 • 1u + 32u + 4 • 16u
= 2u + 32u + 64u=
= 98u
c) (NH4)2CO3 =
2(14u + 4•1u) + 12u + 48u=
2(18u) + 12u + 48u=
36u + 12u + 48u =
=96u