Odpowiedź :
Odpowiedź:
NA2S= 78g/mol
1 mol - 78 g
x mol - 234g
x= 3mole
cm=n/v=3/10=0.3mol/dm3
2.
NaOH=40g/mol
40 g - 1 mol
20g - x =0.5mol
cm=n/v
v= n/cm= 0.5/2.5= 0,2dm3
Odpowiedź:
NA2S= 78g/mol
1 mol - 78 g
x mol - 234g
x= 3mole
cm=n/v=3/10=0.3mol/dm3
2.
NaOH=40g/mol
40 g - 1 mol
20g - x =0.5mol
cm=n/v
v= n/cm= 0.5/2.5= 0,2dm3