Odpowiedź:
zad2
[tex]\frac{(5^8)^2:5^4*5^8}{5^{10}*(-5)^{15}:5^4} =\frac{5^{16-4+8}}{(-5)^{10+15-4}} =\frac{5^{20}}{(-5)^{21}} =(-5)^{20-21}=(-5)^{-1}=-\frac{1}{5}[/tex]
zad3
[tex](\sqrt{2\frac{34}{81} } :\sqrt[3]{\frac{343}{512} } +\sqrt{7\frac{1}{9} } } )*\sqrt[3]{5\frac{104}{125} } =(\sqrt{\frac{196}{81} } :\frac{7}{8} )*\sqrt[3]{\frac{729}{125} } =(\frac{14}{9} *\frac{8}{7} )*\frac{9}{5} =\frac{16}{9} *\frac{9}{5} =\frac{16}{5} =3\frac{1}{5}[/tex]
zad4
[tex]\sqrt[3]{10^2+3^2+2^4} *\sqrt{8} *\sqrt{1,5} *\sqrt{3} =\sqrt[3]{100+9+16} *\sqrt{8*1,5*3} =\sqrt[3]{125}*\sqrt{36} =5*6=30[/tex]
Szczegółowe wyjaśnienie:
