👤
Rozwiązane

Usuń niewymierność z mianownika​

Usuń Niewymierność Z Mianownika class=

Odpowiedź :

Keuawe2351go

Odpowiedź:

1)

[tex] \frac{2}{ \sqrt{7} } \times \frac{ \sqrt{7} }{ \sqrt{7} } = \frac{2 \sqrt{7} }{7} [/tex]

2)

[tex] \frac{5}{ \sqrt{5} } \times \frac{ \sqrt{5} }{ \sqrt{5} } = \frac{5 \sqrt{5} }{5} = \sqrt{5} [/tex]

3)

[tex] \frac{10}{ \sqrt{2} } \times \frac{ \sqrt{2} }{ \sqrt{2} } = \frac{10 \sqrt{2} }{2} = 5 \sqrt{2} [/tex]

4)

[tex] \frac{ \sqrt{2} }{ \sqrt{5} } \times \frac{ \sqrt{5} }{ \sqrt{5} } = \frac{ \sqrt{10} }{5} [/tex]

5)

[tex] \frac{2 \sqrt{5} }{ \sqrt{2} } \times \frac{ \sqrt{2} }{ \sqrt{2} } = \frac{2 \sqrt{10} }{2} = \sqrt{10} [/tex]

Magdago

Odpowiedź:

[tex]1)\ \ \ \ \dfrac{2}{\sqrt{7}}=\dfrac{2}{\sqrt{7}}\cdot\dfrac{\sqrt{7}}{\sqrt{7}}=\dfrac{2\sqrt{7}}{\sqrt{7}\cdot\sqrt{7}}=\dfrac{2\sqrt{7}}{7}\\\\\\2)\ \ \ \ \dfrac{5}{\sqrt{5}}=\dfrac{5}{\sqrt{5}}\cdot\dfrac{\sqrt{5}}{\sqrt{5}}=\dfrac{5\sqrt{5}}{\sqrt{5}\cdot\sqrt{5}}=\dfrac{\not5\sqrt{5}}{\not5}=\sqrt{5}\\\\\\3)\ \ \ \ \dfrac{10}{\sqrt{2}}=\dfrac{10}{\sqrt{2}}\cdot\dfrac{\sqrt{2}}{\sqrt{2}}=\dfrac{10\sqrt{2}}{\sqrt{2}\cdot\sqrt{2}}=\dfrac{\not10^5\sqrt{2}}{\not2_{1}}=5\sqrt{2}[/tex]

[tex]4)\ \ \ \ \dfrac{\sqrt{2}}{\sqrt{5}}=\dfrac{\sqrt{2}}{\sqrt{5}}\cdot\dfrac{\sqrt{5}}{\sqrt{5}}=\dfrac{\sqrt{2}\cdot\sqrt{5}}{\sqrt{5}\cdot\sqrt{5}}=\dfrac{\sqrt{10}}{5}\\\\\\5)\ \ \ \ \dfrac{2\sqrt{5}}{\sqrt{2}}=\dfrac{2\sqrt{5}}{\sqrt{2}}\cdot\dfrac{\sqrt{2}}{\sqrt{2}}=\dfrac{2\sqrt{5}\cdot\sqrt{2}}{\sqrt{2}\cdot\sqrt{2}}=\dfrac{\not2\sqrt{10}}{\not2}=\sqrt{10}[/tex]

Go Studier: Inne Pytanie