Odpowiedź:
a)[tex]\sqrt{48} -\sqrt{27} =4\sqrt{3} -3\sqrt{3} =\sqrt{3}[/tex]
b)[tex]\sqrt{18} +\sqrt{98} =\sqrt{9*2} +\sqrt{49*2} =3\sqrt{2} +7\sqrt{2} =10\sqrt{2}[/tex]
c)[tex]\sqrt{800} +\sqrt{242} +\sqrt{162} =\sqrt{400*2} +\sqrt{121*2} +\sqrt{81*2} =20\sqrt{2} +11\sqrt{2} +9\sqrt{2} =40\sqrt{2}[/tex]
d)[tex]\sqrt[3]{375} =\sqrt[3]{125*3} =5\sqrt[3]{3}[/tex]
Szczegółowe wyjaśnienie:
