Odpowiedź:
[tex]c)\ \ \sqrt{200}-\sqrt{162}+\sqrt{2}=\sqrt{100\cdot2}-\sqrt{81\cdot2}+\sqrt{2}=10\sqrt{2}-9\sqrt{2}+\sqrt{2}=2\sqrt{2}\\\\\\d)\ \ \sqrt{63}+3\sqrt{7}-\sqrt{28}=\sqrt{9\cdot7}+3\sqrt{7}-\sqrt{4\cdot7}=3\sqrt{7}+3\sqrt{7}-2\sqrt{7}=4\sqrt{7}\\\\\\e)\ \ 5\sqrt{11}-\sqrt{44}+\sqrt{99}=5\sqrt{11}-\sqrt{4\cdot11}+\sqrt{9\cdot11}=5\sqrt{11}-2\sqrt{11}+3\sqrt{11}=6\sqrt{11}[/tex]
